Using eqn (4) we want to know the number of moles for a truly dissolved
PAni (EB) of a 1% concentration in DMSO by taking a solvent temperature
of 500 K, and assuming
G
just slightly negative, but around Zero. Then (4) turns to be
(6) nP = (-
H/RT
- nS ln
S) /
lnP = (- 50,000/RT + 0.01) / (-4.6) = 2.62
Even with these very conservative and (for the "solution hypothesis") optimistic assumptions, a 1% concentrated solution of EB in DMSO would only be feasible (according to this estimation) if the molecular weight were so low that 1% is equal to 2,62 Mol. This would be equivalent to a molecular weight of 0.25, i.e.: EB is not soluble! This does not change very much with calculating for a 0.1 % concentration.
A polymer, which cannot be molded, cannot be dissolved [1] (the solvent cannot introduce the melt enthalpy, and we cannot heat the solvent above melting point, because it would boil earlier, and because PAni does not melt at all, hence the solvent cannot replace all of the interchain and intramolecular interactions by monomer unit / solvent interactions).
It is therefore not surprising that in the serie of (neutral, un-doped)
digomeric n-thiophenes the heptamer has no melting point and is insoluble
[2]. The m.p. increases steadily (linearly?)
from ...ºC (for n = 2) to ...ºC (for n = 6).